Programming

Question

Programming

Manu · Accepted Answer

Solution:

import tkinter as tk
from tkinter import messagebox

def input_cards():
    hand = [[0 for _ in range(13)] for _ in range(4)]
    suits = {'C': 0, 'D': 1, 'H': 2, 'S': 3}

    for i in range(5):
        try:
            denomination = int(entries[i][0].get().strip()) - 1
            suit = suits[entries[i][1].get().strip().upper()]
            hand[suit][denomination] = 1
        except:
            messagebox.showerror("Input Error", "Please enter valid card values.")
            return None

    return hand

def display_hand_type():
    hand = input_cards()
    if hand is None:
        return

    if is_flush(hand) and is_straight(hand):
        result.set("The hand is a straight flush.")
    elif is_four_of_a_kind(hand):
        result.set("The hand is four of a kind.")
    elif is_full_house(hand):
        result.set("The hand is a full house.")
    elif is_flush(hand):
        result.set("The hand is a flush.")
    elif is_straight(hand):
        result.set("The hand is a straight.")
    elif is_three_of_a_kind(hand):
        result.set("The hand is three of a kind.")
    elif is_two_pair(hand):
        result.set("The hand is two pair.")
    elif is_one_pair(hand):
        result.set("The hand is one pair.")
    else:
        result.set("The hand is none of the above.")

def is_flush(hand):
    for suit in hand:
        if sum(suit) == 5:
            return True
    return False

def is_straight(hand):
    count = 0
    for i in range(13):
        for suit in hand:
            if suit[i] == 1:
                count += 1
                break
        else:
            count = 0
        if count == 5:
            return True
    return False

def is_four_of_a_kind(hand):
    for i in range(13):
        if sum(hand[suit][i] for suit in range(4)) == 4:
            return True
    return False

def is_full_house(hand):
    three = False
    two = False
    for i in range(13):
        count = sum(hand[suit][i] for suit in range(4))
        if count == 3:
            three = True
        elif count == 2:
            two = True
    return three and two

def is_three_of_a_kind(hand):
    for i in range(13):
        if sum(hand[suit][i] for suit in range(4)) == 3:
            return True
    return False
5C
def is_two_pair(hand):
    pairs = 0
    for i in range(13):
        if sum(hand[suit][i] for suit in range(4)) == 2:
            pairs += 1
    return pairs == 2

def is_one_pair(hand):
    for i in range(13):
        if sum(hand[suit][i] for suit in range(4)) == 2:
            return True
    return False

root = tk.Tk()
root.title("Poker Hand Evaluator")

# Instructions
denominations_label = tk.Label(root, text="Denomination:
Ace=1, Jack=11, Queen=12, King=13")
denominations_label.grid(row=0, column=0, columnspan=2, sticky="w")

suits_label = tk.Label(root, text="Suit: Diamonds=D, Hearts=H, Clubs=C, Spades=S")
suits_label.grid(row=0, column=2, columnspan=2, sticky="w")

# Card inputs
entries = []
for i in range(5):
    card_label = tk.Label(root, text=f"Card #{i+1}:")
    card_label.grid(row=i+1, column=0, sticky="e")
    denomination_entry = tk.Entry(root, width=5)
    denomination_entry.grid(row=i+1, column=1)
    suit_entry = tk.Entry(root, width=5)
    suit_entry.grid(row=i+1, column=2)
    entries.append((denomination_entry, suit_entry))

# Result display
result = tk.StringVar()
result.set("The hand is...")
result_label = tk.Label(root, textvariable=result, width=40)
result_label.grid(row=7, column=0, columnspan=4)

# Display button
display_button = tk.Button(root, text="Display Type of Hand", command=display_hand_type)
display_button.grid(row=6, column=0, columnspan=4)

root.mainloop()

Output of the above program:

Computer science

Computer science

Manu

Answer

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